Mathematics
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OpenStudy (anonymous):
Indicate in standard form the equation of the line through the given points.
K(6, 4), L(-6, 4)
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jimthompson5910 (jim_thompson5910):
same idea as last time....but...we don't have the slope
jimthompson5910 (jim_thompson5910):
so you need to find the slope first
OpenStudy (anonymous):
yeah very similar
jimthompson5910 (jim_thompson5910):
how do you find the slope
OpenStudy (anonymous):
not sure :(
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jimthompson5910 (jim_thompson5910):
use the slope formula
m = (y2 - y1)/(x2 - x1)
jimthompson5910 (jim_thompson5910):
(x1,y1) is your first point
(x2,y2) is your second point
OpenStudy (anonymous):
0
OpenStudy (anonymous):
/-12
jimthompson5910 (jim_thompson5910):
so the slope is?
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OpenStudy (anonymous):
-12
jimthompson5910 (jim_thompson5910):
what did you get for the numerator
OpenStudy (anonymous):
0
jimthompson5910 (jim_thompson5910):
as long as the denominator is not 0, the slope will always be 0 if the numerator is 0
since 0/x = 0
x is any number but 0
jimthompson5910 (jim_thompson5910):
so the slope is 0 instead of -12
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OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
now you have enough info to find the equation
OpenStudy (anonymous):
hmmmm i'm lost
OpenStudy (anonymous):
don't know where to start
jimthompson5910 (jim_thompson5910):
remember you use
y-y1 = m(x-x1)
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OpenStudy (anonymous):
oh right!
jimthompson5910 (jim_thompson5910):
that's why you needed the slope first, you weren't given m (like last time)
so you needed to find m before you could move on
OpenStudy (anonymous):
hmmm so would it be y-4=0?
jimthompson5910 (jim_thompson5910):
close, they want it in standard form
jimthompson5910 (jim_thompson5910):
standard form has the constant all by itself on the right side
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OpenStudy (anonymous):
-y+4?
jimthompson5910 (jim_thompson5910):
y-4 = 0 was close, you just need to get it into the form Ax+By = C
OpenStudy (anonymous):
y=4?
jimthompson5910 (jim_thompson5910):
yep
jimthompson5910 (jim_thompson5910):
that's it
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OpenStudy (anonymous):
Great! thanks a lot you've been a big help
jimthompson5910 (jim_thompson5910):
glad I could be