Question

ax^2+bx+15 is the product of two binomials with integer coefficients. What set has all the possible values of b?

Answer 1

A{8,16}
B{-16,-8,8,16}
C{1,3,5,15}
D{-15,-3,-1,1,-5,15}
It would be B right?

Answer 2

the possiblity of product of two numbers has the result is 15, in order pairs they are (-1,-15),(1,15),(-3,-5),(3,5). if you add up each order pairs,
-1 + (-15) = -16
1 + 15 = 16
-3 + (-5) = -8
3 + 5 = 8
so, the possible values of b is like your choice ;)