Find the limit as x approaches infinity
\[\lim_{x \rightarrow \infty}\frac{ \sqrt{x^{2}-4} }{ 4x-10 }\]
The numerator is factorable
And as a hint : \(\color{blue}{a^2 - b^2} = \color{red}{(a+b)(a-b)}\)
extract x from numerator extract x from denominator cancel x then you have (number-0)/(number-0) <-- comes from taking the limit already
Yeah, I knew that it was factorable, but I don't really know how it helps.
Can you factor that out @selda31 : \(\sqrt{x^2 - 4}\) it is in the form of \(a^2-b^2\) , use the identity stated above to factorize it.
@mathslover Already did, but again, I don't know what to do after factoring it..
Try \[\huge \frac{\sqrt{x^2(1-\frac{4}{x^2})}}{x(4-\frac{10}{x})} \\ \\ \huge \frac{x \sqrt{(1-\frac{4}{x^2})}}{x(4-\frac{10}{x})} \\ \\ \frac{ \sqrt{(1-\frac{4}{x^2})}}{(4-\frac{10}{x})}\]
^^
As \[x \rightarrow \infty , \\ \\ =\frac{1}{4}\]
Oh okay, now I get it. Thanks a lot people
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