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Mathematics 15 Online
OpenStudy (anonymous):

How many combinations of a president, vice-president, secretary, and treasurer can be chosen from a group of 12 students? A.)11,880 B.)95,040 C.)665,280 D.)3,991,680

OpenStudy (raden):

actually, this is a permutation problem. if n elements chosen r element becomes nPr (here n =12 and r 4)

OpenStudy (raden):

so, what's 12P4 ?

OpenStudy (raden):

use the formula : nPr = n!/(n-r)!

OpenStudy (anonymous):

Okay, but is it A, B, C, or D?

OpenStudy (raden):

can you evaluate the value of 12P4 = 12!/(12-4)! = 12!/8! = ...

OpenStudy (anonymous):

I just wanted the answer, but thanks anyways.

OpenStudy (anonymous):

D

OpenStudy (raden):

hmm. the admins OS must be angry to me, if i just give u the ansewer :P hehe.. try it

OpenStudy (anonymous):

I already got the answer from other people.

OpenStudy (raden):

nah, one more u have to know about the factorial : n! = n(n-1)(n-2)(n-3)... 3.2.1

OpenStudy (anonymous):

I believe that it is D

OpenStudy (anonymous):

Like I said, I already got the answer from other people without doing any work.

OpenStudy (anonymous):

K

OpenStudy (anonymous):

I wasn't talking to you lol

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