Question

Use law of cosines to solve for m 12 years ago

Answer 1

Here is the equation
c^(2)=33^(2)+21^(2)-2(33)(21)cos(36)

Answer 2

Well in the question they r asking u to find the value of m<C. but in the equation u have given the value of it is given.

Answer 3

What do you mean? I solved the equation and got c=20.2

Answer 4

i guess the question is to find c and nt m<C

Answer 5

No. Because here are the answer options
82.3 degrees
79.8 degrees
81.3 degrees
80.3 degrees

Answer 6

hmm. is there a diagram for this ques?

Answer 7

Yes. Let me find it

Answer 8

\[c^2=a^2+b^2-2ab\cos C\]
\[\cos C=\frac{a^2+b^2-c^2}{2ab}\]
\[cosC=\frac{(21)^2+(33)^2-(36)^2}{2*21*33}\]

Answer 9

ok, then what.

Answer 10

have u found cosC?

Answer 11

0.17?

Answer 12

yup. nw find \(cos^{-1}0.17\)

Answer 13

79.9?

Answer 14

well its and i have to round to the nearest tenth so 80.3

Answer 15

Actually \(cos^{-1}(0.17)\ne79.9\) but is = 80.21=80.3