Linear programming
To prevent an infection, there are three drugs u, v, w needed. A patient must have at least 20 mg of u, 36 mg of v, w of 14 mg administered to heal. These drugs are commercially available in the form of A-pills and B-powders. An A-pill contains 1 mg of u, 2mg v and 3mg of w and costs 4 euros. A B-powder contains 5 mg of u, 6mg of v and 1mg of w and costs 5 euros. How many pills and powders must purchase a patient to cure as cheap as possible?
Can somone help me with the inequalities?
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i'm not sure which approach to take but i get: y + 2v + 3w = 4 5u + 6v + w = 5 20u + 36v +14w = minimum not sure if the value should be minimum or something else.
Teacher said you have to use x and y.
x = pills Y= powders
my next guess would be: y + 2v + 3w = 4x 5u + 6v + w = 5y 20u + 36v +14w = Ex + Fy
No, the u,v and w are just products said the teacher.
would be a matric like this. the u,v,w column separate, and almost redundant. would be my best guess, lol. \[\left[\begin{matrix}1 & 2 & 3 \\ 5 & 6 & 1 \\ 20 & 36 & 14\end{matrix}\right] \left[\begin{matrix}u \\ v \\w\end{matrix}\right] = \left[\begin{matrix}4x \\ 5y\\ Ex + Fy\end{matrix}\right]\]
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