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Physics 16 Online
OpenStudy (anonymous):

a source is at origin continuously emitting sound at afrequency of 660hz. the sound travels at 330m/s. a listener is moving along the line X=sqroot of (30000) (X in metre ) in +ve direction at contant speed 20m/s.the frequency of sound observed by listener when he is at Y=-100m is a)330 sq root of (3) hz b)sqroot of 20 hz c)330hz d) 680hz

OpenStudy (anonymous):

@AravindG

OpenStudy (anonymous):

@ParthKohli

OpenStudy (anonymous):

@Mertsj

OpenStudy (masumanwar):

This problem can be solved using doppler shift

OpenStudy (masumanwar):

Apparent frequency can be calculated by using formula if observer is in motion towards the source as f=fo(v+u/v-u)

OpenStudy (anonymous):

wat is the answer

OpenStudy (masumanwar):

680 hz

OpenStudy (anonymous):

how is it

OpenStudy (anonymous):

@dhawal whenever you use the doppler effect formula only and only the velocity of obsrvr/source in the line joining the observer and source is to be considered... now try it out you may get the correct ans..;)

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