What is the slope of a line that passes through the point (−2, 3) and is parallel to a line that passes
through (3, 7) and (−2, −8)?
One solution of the equation 2x
2 − x − 10 = 0 is . What is the other solution?
Given the function g(x) = −4x + 5, find g(−4)
3 questions I need help on if anyones willing to help.
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OpenStudy (anonymous):
The other solution is 5/2, and Id prefer if anyone would walk me through it instead of giving me the answer.
OpenStudy (anonymous):
I got 15/5
OpenStudy (anonymous):
The negatives should cancel out since both the numerator and denominator are negative
OpenStudy (anonymous):
For which one?
OpenStudy (anonymous):
Slope=(y2-y1)/(x2-x1)
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OpenStudy (anonymous):
For the lines to be parallel, both equations have the same slope, thus they never touch
OpenStudy (anonymous):
^For Question #1
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
I really dont understand
OpenStudy (anonymous):
Which part?
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OpenStudy (anonymous):
so im finding the the parallel line instead of the slope?
OpenStudy (anonymous):
well, you're finding the slope of the line, which happens to be parallel to another line
OpenStudy (anonymous):
So to find the slope I find the parallel first and then what?
OpenStudy (anonymous):
Do you know how to find the slope with two points?
OpenStudy (anonymous):
no. Thats why I asked whoever would help me to walk me through it
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
slope w/ two points can be found doing (y2-y1)/(x2-x1)
In this case x1=3, y1=7, like point (3, 7) and x2 = -2 and y2= -8 like (−2, −8)
OpenStudy (anonymous):
That gives you (-8-7) *y2-y1* divided by (-2-3) *x2-x1*
OpenStudy (anonymous):
Does this make sense?
OpenStudy (anonymous):
ok so then its -15/-5= 3. Right?
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OpenStudy (anonymous):
Right!
OpenStudy (anonymous):
oh ok!
OpenStudy (anonymous):
lol do you get the parallel line & slope relation?
OpenStudy (anonymous):
^ Parallel lines have the same slope
OpenStudy (anonymous):
yes I do ty. And on the others?
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OpenStudy (anonymous):
K
OpenStudy (anonymous):
for number 3, when you see g(-4), it means you substitute (-4) in for any x values in the equation
OpenStudy (anonymous):
oh! ok! I thought it ment to replace the g
OpenStudy (anonymous):
yeah, it's a little confusing lol
OpenStudy (anonymous):
If you put in the values, you should get 21 for #3
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OpenStudy (anonymous):
I got that but what do I do with the -4 by the g? (or does that dissapear?)
OpenStudy (anonymous):
Technically, it disappears because it means only when x=-4
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
but you could leave g(-4)
OpenStudy (anonymous):
ok. and the last one?
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OpenStudy (anonymous):
what's one of the solutions for #2? The question kind of ends mid-sentence
OpenStudy (anonymous):
the solution thats given is 5/2.
OpenStudy (anonymous):
hmm one sec
OpenStudy (anonymous):
This one's hard -.-'
OpenStudy (anonymous):
I got it!
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OpenStudy (anonymous):
So, since the equation is a polynomial, you can factor the equation
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
do you know how to factor or do you want a walkthrough for it?
OpenStudy (anonymous):
@xNoahx?
OpenStudy (anonymous):
um Im not 100% sure
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OpenStudy (anonymous):
on factoring that is
OpenStudy (anonymous):
all right
OpenStudy (anonymous):
in factoring, you want to make two binomials that, when multiplied, equal to 2x 2 − x − 10 = 0
OpenStudy (anonymous):
how would you do that?
OpenStudy (anonymous):
To start, you know that one set has to be (2x+ or -) and (x+ or -)
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OpenStudy (anonymous):
ok so am I changing the x? Or am I finding a number to add/subtract the other numbers by?
OpenStudy (anonymous):
do you know the FOIL method (first outer inner last) of multiplying?
OpenStudy (anonymous):
yes I do. but how would I use that in this equation?
OpenStudy (anonymous):
okay, to get the leading 2x^2, you multiply the first term of the two binomials
OpenStudy (anonymous):
the only way to get 2x^2 would be by having 2x in one binomial and x in the second
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OpenStudy (anonymous):
ok so It would be (2x+-#) (x+-#)?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
but where do we get the number from?
OpenStudy (anonymous):
to find the # numbers, you have to find two number that, when multiplied by eachother, they equal 10
OpenStudy (anonymous):
so 2 and 5?
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OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
that gives you (2x-5) and (x-2)
OpenStudy (anonymous):
ok so i would be (2x+-2) (x+-5)?
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
I got 2x2-4x-5x-10
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OpenStudy (anonymous):
so, each equation, by default, is set to 0,
so it's 2x-5=0 and x-2=0
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
one sec
OpenStudy (anonymous):
you said foil so I did that. was that wrong?
OpenStudy (anonymous):
no you're right
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OpenStudy (anonymous):
I might have made a mistake. I'll check again
OpenStudy (anonymous):
ok so I add together -4x and -5x right?
OpenStudy (anonymous):
okay, the two binomials are x-2 and 2x+ 5 (not -5)
OpenStudy (anonymous):
oh oops
OpenStudy (anonymous):
lol no my fault
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OpenStudy (anonymous):
so its 2x2-4x+5x-10?
OpenStudy (anonymous):
Shoot
OpenStudy (anonymous):
-.-' I messed up again. It's really (2x-5) and (x+2).
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
sorry about that :(
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OpenStudy (anonymous):
so its 2x2+4x-5x-10?
OpenStudy (anonymous):
?
It should be 2x^2+4x-5x-10
OpenStudy (anonymous):
thats what I put XD
OpenStudy (anonymous):
-.- I'm losing it, aren't I?
OpenStudy (anonymous):
XD its ok! so I add together 4x and -5x?
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OpenStudy (anonymous):
yeah, it simplifies to -x, like the equation
OpenStudy (anonymous):
like before, you set each equation to 0, so it's 2x-5=0 and x-2=0
OpenStudy (anonymous):
then, you solve for x
OpenStudy (anonymous):
so its 2x2-x-10=0?
OpenStudy (anonymous):
yup
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OpenStudy (anonymous):
is it x=2x2-10?
OpenStudy (anonymous):
not quite
OpenStudy (anonymous):
oh...
OpenStudy (anonymous):
2x-5=0 and x-2=0 give you the answers x= 5/2 and x= 2
OpenStudy (anonymous):
oh...
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OpenStudy (anonymous):
when you get the 2 binomials of the equations, you use those to find x's solutions