Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

http://prntscr.com/15hk9l

OpenStudy (anonymous):

@.Sam.

sam (.sam.):

What do you think?

sam (.sam.):

\[x^2-4x-12 \leq 0\] You'll need to factorize this,

sam (.sam.):

\[(x-6)(x+2) \leq 0 \\ \\ x=6 ~~~ x=-2\]

OpenStudy (anonymous):

so D

sam (.sam.):

From the equation, the graph is something like|dw:1368896117917:dw|

sam (.sam.):

Then, it's also 'less than' zero, so its inwards|dw:1368896185679:dw|

sam (.sam.):

We get \[-2 \leq x \leq 6\]

sam (.sam.):

So yeah its D

OpenStudy (anonymous):

http://prntscr.com/15hkuz

OpenStudy (anonymous):

is it B

sam (.sam.):

Factors of 8 are \[\pm 1, \pm 2, \pm 4 ~ and ~ \pm 8\]

sam (.sam.):

Factors of 2 are \[\pm1 ~ and ~ \pm2\]

sam (.sam.):

Yes B

sam (.sam.):

For that we have a curve like this |dw:1368896827680:dw|

OpenStudy (anonymous):

http://prntscr.com/15hlhx

sam (.sam.):

Then it's more than zero, so the vales will be on the outside of the curve|dw:1368896868399:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!