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@.Sam.
What do you think?
\[x^2-4x-12 \leq 0\] You'll need to factorize this,
\[(x-6)(x+2) \leq 0 \\ \\ x=6 ~~~ x=-2\]
so D
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From the equation, the graph is something like|dw:1368896117917:dw|
Then, it's also 'less than' zero, so its inwards|dw:1368896185679:dw|
We get \[-2 \leq x \leq 6\]
So yeah its D
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is it B
Factors of 8 are \[\pm 1, \pm 2, \pm 4 ~ and ~ \pm 8\]
Factors of 2 are \[\pm1 ~ and ~ \pm2\]
Yes B
For that we have a curve like this |dw:1368896827680:dw|
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Then it's more than zero, so the vales will be on the outside of the curve|dw:1368896868399:dw|
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