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Mathematics 15 Online
OpenStudy (anonymous):

Write the expression as a single natural logarithm. 3ln3 + 3lnc A. ln(27 + c3) B. ln9c3 C. ln27c D. ln27c3

OpenStudy (anonymous):

@Mertsj

OpenStudy (anonymous):

@eSpeX

OpenStudy (espex):

What do you know about logs, rattle off some of the rules you know about adding logs.

OpenStudy (anonymous):

yeah I got this one thnx

OpenStudy (anonymous):

I figured out the answer is D

OpenStudy (anonymous):

but can you tell me how do I do the following

OpenStudy (anonymous):

\[\log_{8} 7681\]

OpenStudy (espex):

Is that the extent of the question?

OpenStudy (anonymous):

no that's different one

OpenStudy (anonymous):

I'm just asking how do I do that problem

OpenStudy (espex):

My question was more directed toward there being any instruction or are you just supposed to think of some way to manipulate it?

OpenStudy (anonymous):

I don't know how to do this problem

OpenStudy (anonymous):

\[\log_{8} 7681\]

OpenStudy (espex):

With no instruction I would probably start by converting it to base 10 and seeing if I can break the 7681 apart, then see if I couldn't raise it to a power.

OpenStudy (anonymous):

what instruction u need!!!!!! it's just a math problem

OpenStudy (espex):

Actually it isn't. Right now it is just an expression.

OpenStudy (espex):

If nothing else, evaluate it. What does it equal?

OpenStudy (anonymous):

evaluate what

OpenStudy (anonymous):

I don't know how to do it

OpenStudy (anonymous):

I'm just talking about this problem \[\log_{8} 7681\]

OpenStudy (anonymous):

@eSpeX

OpenStudy (anonymous):

@Ashleyisakitty

OpenStudy (anonymous):

\[\log_{8} 7681= what\]

OpenStudy (espex):

@malkassir I fully understand what you are talking about, what I am trying to tell you is that it is just an expression the same as 7x or 10 is. With you direction the best you can do is to say what it evaluates to. Unless you are good with base 8, I would suggest converting it to base 10 and working the problem. \[\log_{8} 7681\rightarrow \frac{\log_{10}7681}{\log_{10}8} = ~?\]

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