Question

Algebra simplification quick question

Answer 1

(A-1)/(A^4-1)

Is the answer simply A^3 or am I missing something here?

Answer 2

I think you're missing something since it should be \[\frac{1}{1+A+A^2+A^3}\]

Answer 3

I thought the -1's would have just cancelled out and then laws of incides applies, hmm.

Answer 4

Remember that in general \[\frac{A^n-1}{A-1}=A^{n-1}+A^{n-2}+...+A+1.\]So you take the reciprocal, and let \(n=4\), and you get what I just posted.

Answer 5

Ah I see, thanks, my solution makes sense now!

Answer 6

You're welcome.