if a series is absolutely convergent, then it is also convergent?
hi! it's false right?
It's true...
hmm what if
{An} and {Bn} are convergent, then {An}+{Bn} must be convergent?
this is also true i guess
Yup :)
what if {An} and {Bn} both divergent, then {An} - {Bn} must be divergent?
It's true...absolute convergence implies the convergence of the series as the terms go to infinity.
Of course not, what if An=Bn ? then An-Bn = 0 for all n, and is obviously convergent.
\[0 \le Bn \le An and \sum_{?}^{?} (An) converges, then \sum_{?}^{?}(Bn) converges?\]
^that is true. If a bigger series converges, then it makes sense that a smaller series also converges, right?
That's called the comparison test.
\[a sequence {An} converges \to \frac{ 1 }{ 2 } , then \sum_{\infty}^{n=1}(An) must diverge?\]
a sequence An converges to*
For a series to be convergent, then its underlying sequence must converge... to ZERO.
oh i see
And by underlying sequence I believe what he's referring to the sequence of the increments by which each successive term in the sequence of partial sums increases by.
^ So if the sequence which generates the series does not converge to zero (either it converges to something else, or it diverges), then the series must be divergent.
\[a sequence {An} converges \to \frac{ 1 }{ 2 } , then \sum_{\infty}^{n=1}(An) must diverge?\]
so for this one
So for this one, what do you think?
it not true
......if you have a shirt then you have at least one cloth.......T/F..same thing
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