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\[\sum_{n=1}^{\infty} \frac{ n! }{ (n+5)! }\] if i use the ratio test on this is the answer 1/5?
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the answer i get is 1
\[\frac{ (n+1)! / (n+6)! }{ (n+5)!/n! } = \frac{ (n+1)*n! /n!*(n+1)(n+2)... (n+5)(n+6) }{ (n+1)(n+2)...(n+5)*n!/n! }\] taking the limit as n approaches infinity = 1
some cut off
\[\frac{ n+1 }{ n+6 }\]
I trust your answer more than mine, it looks like you know your stuff better ;)
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hehe :) i love calculus
:( calc kills me
hehe. it means no harm :)
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