Question

8 12 years ago

Answer 1

im so lost

Answer 2

finding x?

Answer 3

ya solutions for it

Answer 4

solving for inequalities works the same as solving for equalities.

you want to isolate x while keeping the inequality sign.

8 < 7x - x^2 ------> x^2 - 7x + 8 < 0

use your favorite method to solve for x :)

quadratic works well

Answer 5

when i solved it i got m>0.5833

Answer 6

you should get 2 solutions for x since it's a second-order equation

Answer 7

using quadratic x's are \[\frac{ 7 \pm \sqrt{17} }{ 2 }\]

Answer 8

\[\frac{ 7 - \sqrt{17} }{ 2 } < x < \frac{ 7 + \sqrt{17} }{ 2 } \]

Answer 9

wow i have no idea what you just said

Answer 10

i must be really stupid i got it by 8<x(7-x)
8<7x-2x
8/5<5x/5

Answer 11

@hazel123
8<x(7-x)
8<7x-2x

Your mistake is with distributing x on the right side:
8 < x * 7 - x * 2
8 < 7x - x^2
The last term on the right side is -x^2, not - 2x

Answer 12

so after that what would the steps be

Answer 13

what level algebra is this

Answer 14

maybe Algebra 2

Answer 15

oh wow im in first semester algebra 1

Answer 16

Did you copy the problem correctly?

Answer 17

well i have answer options so maybe that was the way to do it for now

Answer 18

yes

Answer 19

Euler271 already solved it correctly above. Does any of your answers match his solution?

Answer 20

-2

Answer 21

2*

Answer 22

What are your choices?

Answer 23

8

Answer 24

2

Answer 25

-1

Answer 26

0

Answer 27

i can figoure it out obviously when i plug them in

Answer 28

You just wrote an inequality in you original post without instructions. Euler271 solved it correctly and gave you the correct solution. What were the exact instructions with this problem? Which is a solution to the following inequality?

Answer 29

Just plug in each number from your choices and see which one works.