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Mathematics 6 Online
OpenStudy (anonymous):

In a population of 10,000 adults, 20% are smokers. A simple random sample of 600 of the adults is drawn. The SE of the number of smokers in the sample is closest to 9.45 9.5 9.55 9.6 9.65 9.7 9.75 9.8 9.85 9.9

OpenStudy (anonymous):

SE=SQRT(600*0.2*0.8)=9.7979

OpenStudy (anonymous):

yeah.. i too got same answer but it is wrong.

OpenStudy (mario007):

And the correction factor????

OpenStudy (anonymous):

With correction factor it is 9.49994 \[SE=\sqrt{np(1-p)} \sqrt{\frac{ N-n }{ N-1 }}\]

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