In a population of 10,000 adults, 20% are smokers. A simple random sample of 600 of the adults is drawn.
The SE of the number of smokers in the sample is closest to

9.45
9.5
9.55
9.6
9.65
9.7
9.75
9.8
9.85
9.9

Question

In a population of 10,000 adults, 20% are smokers. A simple random sample of 600 of the adults is drawn.
The SE of the number of smokers in the sample is closest to


9.45
9.5
9.55
9.6
9.65
9.7
9.75
9.8 
9.85
9.9

anonymous · Answer

SE=SQRT(600*0.2*0.8)=9.7979

anonymous · Answer

yeah.. i too got same answer but it is wrong.

mario007 · Answer

And the correction factor????

anonymous · Answer

With correction factor it is 9.49994
$$SE=\sqrt{np(1-p)} \sqrt{\frac{ N-n }{ N-1 }}$$