Question

(3x)^lg3=(4x)^lg4

Answer 1

this looks terrible XD

Answer 2

:D

Answer 3

Well...
\[\Large 3x = (4x)^{\frac{\lg4}{\lg 3}}\]

Answer 4

But I'm guessing you already did this? :D

Answer 5

\[\large 3x = (4x)^{\log_3 4}\]

Answer 6

Yes but i lost my ans sheet-.-

Answer 7

The solutions I mean.Bt ans will be(1/12)

Answer 8

Okay... new plan...
\[\LARGE x = \frac{4^{\log_34}x^{\log_34}}{3}\]

Answer 9

\[\LARGE \frac{x}{x^{\log_34}}=\frac{4^{\log_34}}3\]

Answer 10

\[\LARGE x^{1-\log_34}=\frac{4^{\log_34}}3\]

Answer 11

X=1/12 Thats the answer though

Answer 12

Its late

Answer 13

then its ok

Answer 14

I think ill just solve this later

Answer 15

\[\LARGE x^{\log_3\frac34}= \frac{4^{\log_34}}{3}\]
\[\LARGE x = \frac{4^{\frac{\log_34}{\log_3\frac34}}}{3^{\frac1{\log_3\frac34}}}\]

Answer 16

Cool so where do we go from therexD

Answer 17

Well, change of base again...
\[\LARGE x = \frac{4^{\log_{\frac34}4}}{3^{\log_{\frac34}3}}\]

Answer 18

This really brings back memories... this was destiny...

Answer 19

lol.Im stuck at here