Please help !
The functions f(theta) and g(theta) are sine functions, where f(0) = g(0) = 0. The amplitude of f(theta) is twice the amplitude of g(theta). The period of f(theta) is one-half the period of g(theta). If g(theta) has a period of 2pi and f pi/4 = 4, write the function rule for g(theta)

Question

Please help !
The functions f(theta) and g(theta) are sine functions, where f(0) = g(0) = 0. The amplitude of f(theta) is twice the amplitude of g(theta). The period of f(theta) is one-half the period of g(theta). If g(theta) has a period of 2pi and f pi/4 = 4, write the function rule for g(theta)

angelwings996 · Answer

@satellite73 could you help me?

anonymous · Answer

The general formula of the sine function is:
y = a * sin(bx - c)

Where a is the amplitude, 2pi/b is the period, and c is the phase shift. Do you think you see how you can use the information above to depict f(theta) and then g(theta) in the form above?

angelwings996 · Answer

Yes

angelwings996 · Answer

what would the phase shift be ?

anonymous · Answer

In this problem, I believe f(theta) would have a phase shift of 0. g(theta) is most likely the same.

angelwings996 · Answer

So would it be something like : y = a*sin(2pi/bx-0) ?

angelwings996 · Answer

@Pompeii00

anonymous · Answer

Did u ever get the answer?

anonymous · Answer

Btw did u finish this test?