Earthquakes release seismic waves that occur in concentric circles from the epicenter of the earthquake. Suppose a seismograph station determines the epicenter of an earthquake is located 9 kilometers from the station. If the epicenter is located at the origin, write the equation for the circular wave that passes through the station.
if the center of the circle is at the origin and the station is 9 kilometers from the center that means that the radius is 9 and you should easily be able to determine the equation of a circle with the given informaion
A x2 + y2 = 81 B x2 + y2 = 9 C (x - 9)2 + (y - 9)2 = 0 D (x + 9)2 + (y + 9)2 = 0
you already know (from the previous question) that the equation of a circle is \[(x - h)^{2} = (y - k)^{2} = r^{2}\] it said that the center is at the origin (If the epicenter is located at the origin...) so (h, k) = (0, 0). since the station is 9 km away, the radius (r) will be 9. plug in those values and you should have it.
I do online school so its really hard :( to learn math on my own and i have 17 days left to finish everything
the previous question has nothing to do with this question
circle equation \[(x-x_0)^2+(y-y_0)^2=r^2\] where (xo,yo) is the location of the center of the circle and r is the radius
So A?
i already gave you everything you need to solve the problem so have more confidence in your own abilities
but yes its right
Right the radius is 9 so 9 squared is 81?
okay thank you soooo much :DD
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