solve for x in the given interval
sinxtan3x=0(-pi,0)

Question

solve for x in the given interval
sinxtan3x=0(-pi,0)

anonymous · Answer

$$sinxtan3x=0(-\pi,0)?$$

anonymous · Answer

$$well, x = 2 \pi n ~~ 6.2832 n and n element Z$$

anonymous · Answer

$$x = 0$$

anonymous · Answer

how did you get the 0? I got the -pi

anonymous · Answer

also there is a couple more answers

anonymous · Answer

sin x tan x=0  (-pi,0)
either sin x=0=sin npi ,where n is an integer.
x=-pi,x=0
if (-pi,0) is an open interval, then there is no solution.
or tan x=0=tan npi,where n is an integer.
x=-pi,0 in the closed interval ( pi,0)
in the open interval it has no solution.

anonymous · Answer

correction
tan 3x=0=tan npi ,where n is an integer.
3x=n pi,x=npi/3    (put n/3=-1,n=-3)
for n=-3,-2,-1,0
x=-pi,-2pi/3,-pi/3,0

anonymous · Answer

for open interval x=-2pi/3,-pi/3 are the solutions.

anonymous · Answer

how are you getting the npi thing? what is that? and what values do you plug into that