Question

solve for x in the given interval
sinxtan3x=0(-pi,0)

Answer 1

\[sinxtan3x=0(-\pi,0)?\]

Answer 2

\[well, x = 2 \pi n ~~ 6.2832 n and n element Z\]

Answer 3

\[x = 0\]

Answer 4

how did you get the 0? I got the -pi

Answer 5

also there is a couple more answers

Answer 6

sin x tan x=0 (-pi,0)
either sin x=0=sin npi ,where n is an integer.
x=-pi,x=0
if (-pi,0) is an open interval, then there is no solution.
or tan x=0=tan npi,where n is an integer.
x=-pi,0 in the closed interval ( pi,0)
in the open interval it has no solution.

Answer 7

correction
tan 3x=0=tan npi ,where n is an integer.
3x=n pi,x=npi/3 (put n/3=-1,n=-3)
for n=-3,-2,-1,0
x=-pi,-2pi/3,-pi/3,0

Answer 8

for open interval x=-2pi/3,-pi/3 are the solutions.

Answer 9

how are you getting the npi thing? what is that? and what values do you plug into that