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deltaH comb for sucrose can be calculated by deltaH comb=(Csystem deltaT)/n, where the moles of sucrose in the sample and C system is the heat capacity of the calorimetric system. Using the value you calculated for C system, calculate the heat of combustion for sucrose.
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I have this much done DeltaH=327.184(1.701)/n
but what is DeltaH supposed to be?
\(\Delta H\) = change in enthalpy or heat energy
The initial temperature for sucrose was 25.000C and the final temperature was 26.701. Would \[\Delta H\] be 1.701?
but I already have that answer for \[\Delta T\]
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Hmm \[\Delta H=\frac{Q}{n}\] And \(Q=mc \Delta T\)
what is mc?
@abb0t @.Sam.
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