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What is the general form of the equation of a circle with a center at the (4, –2) and a radius of 9?
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A(x – 4)^2 + (y – 2)^2 = 81 B (x – 4)^2 + (y + 2^)2 = 81 C(x + 4^)2 + (y – 2)^2 = 81 D(x + 4)^2 + (y + 2)^2 = 81
The general equation of a circle with centre (h,k) and radius r is \[(x-h)^2+(y-k)^2=r^2\]
Use that here
(x-4)^2+(y+2)^2=9^2
(x^2+8)+(y^2+4)=81
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oh, 16?
(x^2+16)+(y^2+4)=81
(x-4)^2+(y+2)^2=9^2 IS RIGHT
9^2=81
ya that's what I did
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Now what do I do?
@AravindG
Nothing left !
You got the answer :)
OH, LOL thanks!
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lol Option B :)
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