According to Boyle's Law, what was the volume (to the nearest integer) at the time of the first measurement given the following information?
P1 = 5.42 atm
P2 = 8.59 atm
V2 = 527 mL
A. 1671 mL
B. 835 mL
C. 333 mL
D. 168 mL

Question

According to Boyle's Law, what was the volume (to the nearest integer) at the time of the first measurement given the following information?
P1 = 5.42 atm
P2 = 8.59 atm
V2 = 527 mL
	A.	1671 mL
	B.	835 mL
	C.	333 mL
	D.	168 mL

whpalmer4 · Answer

Boyle's law is that the absolute pressure of a given mass of an ideal gas varies inversely with its volume if temperature and amount of gas remain constant.  This implies that 

$$P_1V_1 = P_2V_2$$

whpalmer4 · Answer

You know all but $V_1$, so rearrange the equation to give you $V_1 = $ and plug in the values you have.

anonymous · Answer

Okay I'll plug them in :D

anonymous · Answer

Boyle's Law:  The absolute pressure exerted by given mass of an ideal gas is inversely proportional to the volume it occupies if the temperature and amount of gas remain unchanged within a closed system.

So,   PV = k

(8.59)(527) = k     ->     k = 4526.93    This is for the second set of P,V

For the first set:

(5.42)(V) = 4526.93     ->      V = 4526.93 / 5.42

So, the first V is 835.22693726937269372693726937269

anonymous · Answer

PV = k    is why you can set:   (P1)(V1) = (P2)(V2)   because they both equal k.

anonymous · Answer

now that makes since

anonymous · Answer

the next questions is one of those newton questions