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A force of 100 Newtons will stretch a spring 0.25 meter. How far will a force of 80 Newtons stretch it? A. 2 m B. 0.2 m C. 0.04 m D. 0.4 m
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It's a straightforward proportion, because Hooke's Law is \(F=kx\), when the deformations are small enough. You've got values for \(F\) and \(x\) which you can use to find \(k\) to apply to your second value of \(x\).
Or, observing that the force/deformation is linear, multiply the ratio of the deformations with the known force to get the other force.
Sorry, ratio of the forces with the known deformation...
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