Janet has a jar of 54 coins consisting of dimes and quarters. If she has a total of $8.70, how many dimes does she have? 22 24 30 32
Let the number of dimes = d Let the number of quarters = q Using d and q, what is the total number of coins?
You have two equations here. Let D be the number of dimes, and Q be the number of quarters. Then we know that \(D + Q = 54\) because we have 54 coins, and they are only dimes and quarters. Similarly, we know that a dime is worth 10 cents and a quarter is worth 25 cents. Remembering that 1 dollar is 100 cents, can you write an equation in terms of D and Q that gives you the value of the coins, in cents? With that equation and the first equation, you can solve for D and Q.
A slightly different way to write this would be strictly in terms of dimes. There you would say you have D dimes. Clearly, the number of quarters would be 54 - D. Now you can write an equation using D for the number of dimes and 54 - D for the number of quarters, multiplying each by the value of the respective coin, and adding up to the total value.
Yet another way: figure out the value of 54 dimes and 54 quarters, respectively. Compare the value of the jar ($8.70) with those two values. If the value of the jar was 1/3 of the way between the extremes of 54 dimes / 0 quarters and 0 dimes / 54 quarters, the number of coins would also be 1/3 of the way. Or you could "trade off" dimes for quarters until you got to the right value. Start with 54 dimes = $5.40. The number of coins remains constant, so every 4 quarters you add ($1) takes away 4 dimes ($0.40), meaning you can inch along the line by $0.60 for every 4 dimes converted to quarters. $5.40, $6, $6.60, $7.20, etc. When you get closer, you'll have to switch to trading off a single coin.
22 dimes 26 quarters = 8.70
@Mpk15 Way to help the OP learn how to solve these problems!
no problem
its not 22 dimes.
22 dimes + 26 quarters = 48 coins The problem states there are 54 coins.
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