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Mathematics 14 Online
OpenStudy (anonymous):

Solve: |5x + 2| + 7 < 19 A. x < 2 and x > -14/5 B. x < 2 and x < -14/5 C. x > 2 and x > 14/5 D. x > 2

OpenStudy (anonymous):

@nguyen8ki

OpenStudy (anonymous):

the first thing you want to do is that you want to get rid of the absolute value sign this leads to 2 cases: |5x+2| = 5x+2 if x>-2/5 or |5x+2| = -(5x+2) if x<-2/5 then we have a system of two equations: 5x+2+7<19 if x>-2/5 or -(5x+2)+7<19 if x<-2/5 5x+9 <19 -5x+5 <19 -9 -9 -5 -5 _____________________________________________________ 5x < 10 or -5x <14 x < 2 and (x>-2/5) or x >-14/5 and (x<-2/5) -2/5<x<2 or -14/5<x<-2/5 combine the two conditions we have the final answer -14/5<x<2 so A PS: it is a little complicated when you look at the signs and combine the conditions, the key words here are " and" and " or". these two words make the difference.

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