According to Boyle's Law, what was the pressure (to the nearest tenth) at the time of the first measurement given the following information?
V1 = 7450 mL
P2 = 8.25 atm
V2 = 1645 mL
A. 37.4 atm
B. 4.52 atm
C. 0.5 atm
D. 1.8 atm

Question

According to Boyle's Law, what was the pressure (to the nearest tenth) at the time of the first measurement given the following information?
V1 = 7450 mL
P2 = 8.25 atm
V2 = 1645 mL
	A.	37.4 atm
	B.	4.52 atm
	C.	0.5 atm
	D.	1.8 atm

ddcamp · Answer

Boyle's law: 
P₁V₁ = P₂V₂
So:
P₁ = (P₂V₂)/(V₂)

kinggeorge · Answer

Also, this should probably be asked in the chemistry section, and not mathematics.

anonymous · Answer

NO its a math question not a chemistry question. Math Modules