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Mathematics 22 Online
OpenStudy (anonymous):

What is the area of the shaded region in the figure below?

OpenStudy (anonymous):

OpenStudy (anonymous):

a. 32π −16 b. 16π − 16 c. 32π − 32 d. 16π − 32

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

Hint: Area of Shaded Region = (Area of Circular Pie Shaped Piece) - (Area of Triangle)

OpenStudy (anonymous):

@jim_thompson5910 i don't get it..

OpenStudy (jdoe0001):

and I assume you know what the Area of a triangle is, if not, check your formulas sheet

OpenStudy (anonymous):

i still don't understand @jdoe0001

OpenStudy (jdoe0001):

your graphic shows an "arc" or so-called "sector of a circle", you use the formula there THEN you use the triangle formula to get the non-shaded triangular area, and substract that form the sector's

OpenStudy (anonymous):

i get that but it's the equation that's confusing me

OpenStudy (jdoe0001):

ok, lemme rewrite it

OpenStudy (jdoe0001):

$$ \cfrac{\color{red}{\theta} r^2}{2}\\ \textrm{mind you that } \color{red}{\theta} \text{ should in radians} $$

OpenStudy (jdoe0001):

in this case \(\large 90^o = \frac{\pi}{2} \)

OpenStudy (anonymous):

okay so should i cross multiply that?

OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

$$ \cfrac{\color{red}{\theta} r^2}{2} \implies \cfrac{\color{red}{\frac{\pi}{2}} r^2}{2} \implies \cfrac{\color{red}{\pi} r^2}{4} $$

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