f(x)={ -2x^2+3, xor eq 1 x^2+2, x x- the answer is 3, but i keep getting 1.

Question

f(x)={ -2x^2+3, x>or eq 1
           x^2+2,     x<1
lim-> x-                    the answer is 3, but i keep getting 1.

anonymous · Answer

So your question is$$\lim_{x\to1}f(x), \text{ where}\
f(x)=\begin{cases}-2x^2+3&\text{for }x\ge1\x^2+2&\text{for }x<1\end{cases}$$

anonymous · Answer

You are trying to find the limit when x is approaching...? I'm just confused by the syntax.

anonymous · Answer

|dw:1369348822156:dw| approaches 1 from the left

anonymous · Answer

"From the left" means you use the piece for values of x less than 1, so
$$\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(x^2+2)$$

anonymous · Answer

Oh I gotcha now. You need to use the second equation to find the limit, since it is in charge of everything before 1.

anonymous · Answer

And if x is 1, you'd get 3.

anonymous · Answer

you get 3 if you use direct substitution but if i look at the graph on my calc i see 1

anonymous · Answer

When you make the graph on your calculator, are you using the second equation to determine it?

anonymous · Answer

never mind i mixed up my graphs....... aorry

anonymous · Answer

No problem, mistakes happen. Happens to me all the time >.>