8 men and 6 women arrive separately in a random fashion to a meeting. What is the probability that the first 4 people to show up are men? I feel like i can't break this down
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jimthompson5910 (jim_thompson5910):
What is the probability that the first person to show up is a man
OpenStudy (anonymous):
8/14 right
jimthompson5910 (jim_thompson5910):
yep, how about the probability that the second person to show up is a man
Note: the first man has arrived (assume this is true), so take him out of the equation
OpenStudy (anonymous):
7/13
jimthompson5910 (jim_thompson5910):
how about the third
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OpenStudy (anonymous):
6/12 or 1/2 so I just do that till I get to the forth man?
jimthompson5910 (jim_thompson5910):
you can use either one, 1/2 might be easier to use
but 6/12 helps you see the overall pattern
jimthompson5910 (jim_thompson5910):
yes you keep going until you reach the fourth one
jimthompson5910 (jim_thompson5910):
once you get all your fractions, you multiply them out
this works because each event is independent from one another
OpenStudy (anonymous):
5/11 then im multiplying that times something right
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jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
so you have these four fractions
8/14
7/13
6/12
5/11
then you multiply them all out to get ????
OpenStudy (anonymous):
5/11 x 8/14?
jimthompson5910 (jim_thompson5910):
multiply all 4 though
OpenStudy (anonymous):
that was so easy thanks again 10/143
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