Given the function defined by e^sinx for all x such that -pi < or equal to x and x is < or equal to 2pi. Find the x- and y- coordinates of all the maximum and minimum points on that given interval. Justify your answer.
Find any critical points of the function in that interval and find the y-values for these critical points. Then find the y-values for the actual endpoints of the intervals and compare them to find the maximum and minimum points.
I tried that and I don't know if what I've done so far is correct: f(x)=e^sinx F'(x)=(cosx)e^sinx (cosx)e^sinx=0 e^sinx=arccos(0) sinx=ln(arccos(0)) x=arcsin(ln(arccos(0))) x=0.4685
Your algebra is wrong. Remember that of you apply arccos to both sides than it would also have to be applied to the e^sinx(so not really simplifying the equation). A way that you could solve it would to separate both functions and solve separately for when cosx = 0 and for when e^sinx = 0.
^The derivative is correct though :)
Thank you!!
No problem :)
And remember to compare the y-value of those two points to the values of the endpoints of the interval since those can be maximum or minimum values as well.
Okay got it!
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