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Mathematics 13 Online
OpenStudy (anonymous):

How do you factor this?

OpenStudy (anonymous):

x^3 - 4x^2 + 3x - 12

OpenStudy (anonymous):

I got to factoring the first 3 terms x(x^2-4x+3)+12

OpenStudy (anonymous):

What next

OpenStudy (loser66):

@kevincourtes long division, help him,

OpenStudy (loser66):

@LangstonK wrong way friend

OpenStudy (anonymous):

@LangstonK (x^2+3)(x-4)

OpenStudy (loser66):

show your work, @kevincourtes

OpenStudy (anonymous):

Kevin how do you get to there? I already know the answer. just not how to get there

OpenStudy (loser66):

@kevincourtes knock knock

OpenStudy (anonymous):

Mind explaining, loser?

OpenStudy (anonymous):

Think hes not there

OpenStudy (loser66):

hey, not know how to show? ask me for help?

OpenStudy (anonymous):

sorry?

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

Is there a way without synthetic division?

OpenStudy (loser66):

he is off line. now, I guide you horner's rule

OpenStudy (loser66):

want to know?

OpenStudy (anonymous):

ok. because synthetic division is long and repetitive and i dont want to do it during an exam

OpenStudy (loser66):

start at the last number is -12 you have some products of -12 -12 = 12*(-1) -12 = (-12)*1 -12= 4*(-3) -12=3 * (-4) -12= (-2)*6 -12= 6* (-2) If you are lucky, you can get the correct answer at the first time you try, if not, you must try one by one. My experience tells me that I should pick the couple which I can calculate in my head and know it is the right answer, for example, if i pick 12 * (-1) it means -1 must be one of the root, I replace x =-1 into the original function and get (-1)^3 +4 (-1)^2 +3(-1)-12 = -12 (not =0) so -1 cannot be a root, get rid of, do the same you will see only 4* (-3) or (-4)*3 might be right. I pick 4 to try continue?

OpenStudy (loser66):

no shortcut, friend, math need proof and you have to master it.

OpenStudy (anonymous):

So just find the one pair of multiples that equal 0 when plugged x?

OpenStudy (anonymous):

What happens when i find the pair?

OpenStudy (loser66):

not that simple. horner's rule is not apply yet.

OpenStudy (loser66):

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