How do you factor this?
x^3 - 4x^2 + 3x - 12
I got to factoring the first 3 terms x(x^2-4x+3)+12
What next
@kevincourtes long division, help him,
@LangstonK wrong way friend
@LangstonK (x^2+3)(x-4)
show your work, @kevincourtes
Kevin how do you get to there? I already know the answer. just not how to get there
@kevincourtes knock knock
Mind explaining, loser?
Think hes not there
hey, not know how to show? ask me for help?
sorry?
Is there a way without synthetic division?
he is off line. now, I guide you horner's rule
want to know?
ok. because synthetic division is long and repetitive and i dont want to do it during an exam
start at the last number is -12 you have some products of -12 -12 = 12*(-1) -12 = (-12)*1 -12= 4*(-3) -12=3 * (-4) -12= (-2)*6 -12= 6* (-2) If you are lucky, you can get the correct answer at the first time you try, if not, you must try one by one. My experience tells me that I should pick the couple which I can calculate in my head and know it is the right answer, for example, if i pick 12 * (-1) it means -1 must be one of the root, I replace x =-1 into the original function and get (-1)^3 +4 (-1)^2 +3(-1)-12 = -12 (not =0) so -1 cannot be a root, get rid of, do the same you will see only 4* (-3) or (-4)*3 might be right. I pick 4 to try continue?
no shortcut, friend, math need proof and you have to master it.
So just find the one pair of multiples that equal 0 when plugged x?
What happens when i find the pair?
not that simple. horner's rule is not apply yet.
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