Mathematics
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OpenStudy (jkbo):
write the equation of an ellipse with minor axis of length 8 and vertices at (-9,3) and (7,3)
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OpenStudy (mertsj):
The minor axis = 8 tells you that 2b=8
OpenStudy (mertsj):
Can you find the distance from (-9,3) to (7,3)? That distance is the length of the major axis which is 2a
OpenStudy (jkbo):
its 17 units away
OpenStudy (mertsj):
From (-9,3) to (7,3) is 16
OpenStudy (mertsj):
The center is the midpoint of the major axis.
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OpenStudy (jkbo):
so 16 is the midpoint?
OpenStudy (mertsj):
The length of the major axis is 16
OpenStudy (mertsj):
Do you know how to find a midpoint?
OpenStudy (jkbo):
no not at all
OpenStudy (mertsj):
Add the x coordinates and divide by 2. Add the y coordinates and divide by 2. That will give you the midpoint.
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OpenStudy (mertsj):
\[x=\frac{x _{1}+x _{2}}{2}\]
OpenStudy (mertsj):
\[y=\frac{y _{1}+y _{2}}{2}\]
OpenStudy (jkbo):
I got -1,3
OpenStudy (mertsj):
Yes. That is the center.
OpenStudy (mertsj):
Now you just need to plug into the equation of an ellipse:
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OpenStudy (mertsj):
\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\]
OpenStudy (mertsj):
(h,k) is the center.
OpenStudy (jkbo):
what would x and y be?
OpenStudy (jkbo):
@Mertsj
OpenStudy (mertsj):
x and y remain in the equation.
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OpenStudy (jkbo):
ok does a^2 and b^2 stay the same or no?
OpenStudy (mertsj):
Replace a and b with the values you calculated.
OpenStudy (jkbo):
-1,3 again?
OpenStudy (mertsj):
2b=8
OpenStudy (mertsj):
Can you find the distance from (-9,3) to (7,3)? That distance is the length of the major axis which is 2a
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OpenStudy (jkbo):
that 16
OpenStudy (jkbo):
*thats
OpenStudy (mertsj):
Yes. 2a = 16
OpenStudy (jkbo):
b^2 is 8 and a^2 is 16
OpenStudy (mertsj):
2b=8
Solve for b
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OpenStudy (mertsj):
Yes. 2a = 16
Solve for a
OpenStudy (jkbo):
its 4
OpenStudy (mertsj):
If b = 4, what is b^2?
OpenStudy (jkbo):
I'm not really sure
OpenStudy (mertsj):
What class are you taking?
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OpenStudy (jkbo):
alg. 2 I just dont know this chapter well
OpenStudy (mertsj):
How is it you don't know how to raise a number to the second power?
OpenStudy (jkbo):
o well 2 to the second power is 4 if that what your asking
OpenStudy (mertsj):
You said that b = 4 and that is correct. I then asked, "what is b^2?" You said you didn't know.
OpenStudy (jkbo):
I thought you want the square root of 16 thats why or what can go into 8 and 2
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OpenStudy (mertsj):
What is a?
OpenStudy (jkbo):
I pretty sure its 4 because of 16
OpenStudy (mertsj):
2a = 16 Solve for a
OpenStudy (jkbo):
I'm not sure what it is I confused
OpenStudy (jkbo):
i'm *
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OpenStudy (mertsj):
So you are telling me that you are in Algebra II, studying ellipses and you cannot solve this equation:
OpenStudy (mertsj):
|dw:1369362904417:dw|