tate the domain of the function f(x)=√X
have you graphed it to see what the function looks like?
oh ok but how would i do that..i mean i know how to graph but not square roots
Are you using a TI? Perhaps a TI-84?
dont know what that is lol..tbh i barely learned anything this yr in MATH 3
If not, you can just try plugging in values for x. And because you cannot plug in negative values for x under a square root, you know your domain starts at 0. from x=0 onwards, you have increasingly larger values that keep going on and on. So, The domain for \[f(x)= \sqrt{x}\] = \[0\le x \le \infty\]
the function f(x) =\[\sqrt{x}\] has the domain of positive real no union 0 or\[R ^{+}u0\]
Ohhhh ok thank youu!
The reason you cannot plug negative values under a square root is because you will get imaginary numbers, you'll learn more about those later :)
lol oh trust me i just learned how to do them lol i remember i = √-1 correct?
Actually.... the domain can be written as i mentioned above, OR like \[x \ge 0\] haha. sorry about that!!
Yes you are right :)
Yay! lol
well thanks for you help i might have another question soon lol
Alrighty :)
oh wait i have this one more question..im on the next question..and i know how to do this problem --> (x+2)(2X²-3x+5) but i just need to know when i multiply x*2x² is it 3x² or 2x³
It's \[2x^3 = (x)(2x^2) = (2)(1)(x ^{2+1})\]
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