the figures are similar. give the ratio of the perimeters and the ratio of the areas of the first figure to the second.
@Loser66
@e.mccormick
Did you find a ratio of the given sides?
18/16= 9/8
my options are 10/9 and 11/10, 10/9 and 81/64, 9/8 and 11/10, 9/8 and 81/64 @Loser66
Yep. That is for linear measure. For square measure, square the ratio! (And like I hinted before, the rule applies to other dimensions as well. So a 7th dimension would have a volume that was to the 7th power... but we would not be able to comprehend seeing it. And I am only bringing up 7 dimensions to teas Loser66 because he objected to my bringing up 3!)
aha... you are teasing me, ok, I won't let it go free. let see.
hehe
well which one of these are the right answer?
The ratios can go either way. 8/9 pr 9/8 mean the same as a ratio of sides.
9/8 what 's else? I give it already. but have to torture the guy who dare teasing me, ok?
but there is two answers to each..
@e.mccormick she said that her options are above, not 8/9 pal.
just 9/8
my 9/8 options come with 11/10 or 81/64.
ooh okay.
sorry, my bad, I am wrong.
can i get one more question in?
well poooo.
9/8 and 81/64 since \[(\frac{9}{8})^2 = \frac{81}{64}\]. am I right @e.mccormick
Yep!
hey, that is 2 dimension as you wish.
Want to see the 7th dimension? =P
heheh..forgive you by quickly respond. ok show me
Oh, sure... he wants to see me take those to the 7th power! \[\left(\frac{9}{8}\right)^7=\frac{4782969}{2097152}\]Really huge ratio at that dimensional volume!
hahahaa.... you rascal.....
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