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Mathematics 11 Online
OpenStudy (anonymous):

find limit: limit as x approaches infinity of (3+x)/(3-x)

OpenStudy (anonymous):

The top approaches infinity, while the bottom also approaches infinity. Do you know L' Hopital's Rule yet?

OpenStudy (anonymous):

no....

OpenStudy (johnweldon1993):

Ahh yes L'Hopital's rule would really help here... first...do you know about derivatives yet?

OpenStudy (anonymous):

nope i just started learning about limits

OpenStudy (anonymous):

When you have an indeterminant form such as infinity/infinity, you can use that rule. But you would need to know about derivatives first, as johnweldon said.

OpenStudy (anonymous):

ok....

OpenStudy (johnweldon1993):

Hang on I'm trying to remember how to do em without that rule :)...

OpenStudy (anonymous):

Well we can always just use common sense here. Since the top approaches the inverse of the bottom, you can say that the answer is -1.

jimthompson5910 (jim_thompson5910):

Hint: divide each piece by x

OpenStudy (anonymous):

Oh yeah she probably knows that anything divided by infinity is 0, so we could do what jim said.

OpenStudy (anonymous):

so the limit is 0?

OpenStudy (anonymous):

So try that @BeautyQueen327 we can divide both the top and bottom by x, giving us: (3/x+1)/(3/x-1)

OpenStudy (anonymous):

3/x, when x approaches infinity, equals 0, because we are dividing by a huuuuge number. So you get (1/-1)=-1

OpenStudy (anonymous):

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