Question

AB is tangent to O. If AO = 48 and BC = 100, what is AB? The diagram is not to scale.

Answer 1

@RadEn

Answer 2

first, AO = CO = radius = 48 and
BO = BC + CO = 100 + 48 = 148
to get the length of AB, use the pythagorean theorem :
AB ^2 = BO^2 - AO^2
so,
AB^2 = (148)^2 - (48)^2
solve for AB

Answer 3

wait 19600?

Answer 4

that just for AB^2 , right ?

Answer 5

AB = sqrt(19600) = ?

Answer 6

oh 140

Answer 7

if u dont like use the calculator :P
u can do it like this
AB^2 = (148)^2 - (48)^2
AB^2 = (148+48)(148-48)
AB^2 = (196)(100)
AB = sqrt(196*100) = sqrt(196) * sqrt(100) = 14 * 10 = 140

you are right

Answer 8

ohhhh okay

Answer 9

Find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to scale.

Answer 10

x^2 = 11^2 + 8^2
solve for x

(if it is hard for u, dont forget use the calculator :P)

Answer 11

sorry, it's time for pray now. i have to going to the mosque
good luck , @coe