The formation of nitric oxide (N2(g) + O2(g) 2NO(g)) has a Kc value of 4.7 � 10-31. A classmate claims that this reaction must really make a lot of nitric oxide since the exponent is such a large value. Explain to the student why her reasoning is correct or flawed. Help? PLEASE :C

Question

The formation of nitric oxide (N2(g) + O2(g)  2NO(g)) has a Kc value of 4.7 � 10-31. A classmate claims that this reaction must really make a lot of nitric oxide since the exponent is such a large value. Explain to the student why her reasoning is correct or flawed. Help? PLEASE :C

anonymous · Answer

@.Sam. could you help me with this one please?

anonymous · Answer

@chmvijay help?

anonymous · Answer

She is right ? right? @chmvijay

anonymous · Answer

This is true, since the Kc value is below 1. You can tell that she is right because of the rule " K < 1 = reactants in favor " So Nitric oxide is on the reactant side and its the side in favor so its exponents would be a large value. @chmvijay

chmvijay · Answer

humnn KC value less than 10-3 favors more reactant and Kc value above 10^3 favors the more product
in ur case u have 10^-31 which very low value hence u wont get nitric oxide and only N@ and O2 will be present in more amount

chmvijay · Answer

No is on the product side :)

chmvijay · Answer

what are u thinking now

chmvijay · Answer

though its large exponential the -ve is there behind means u have to give sooo may zeros in front of a point got it