WXYZ is an inscribed quadrilateral whose diagonals intersect at K. Segment WX is parallel to segment ZY, as shown below. Prove that if angle ZYW is 30° and angle ZWY is 20°, then angle WZX is 100°. Write a two-column proof showing statements and reasons.
@RadEn @xozombie @Xmoses1 @trumpetmaster7777 @him1618 @LaShaun97
@Xmoses1 PLEASE HELPP!
does it mean in paragraph form or just two lines?
2 colum, statement & justification
hhmm ok
@RadEn what do you think? i am not too familiar with this
The two crossing line form perpendicular lines. Would it have anything to so with the vertical angles theorem?
i saw the angle of <WZX is an acute angle, so it cant be 100 deg, right ?
Thats what it looks like to me. It would be easier if the angle we were trying to prove was complimentary
It is also not a regular polygon
I'm very confused lol
ZY and WX are parallel so we know that the alternate interior angles should be the same
yes, so then you go on from there lol
Oh haha i forgot that was a given. lol
yes, so we have ZY and WX are parallel---given
Segment WX is parallel to segment ZY, given Alternate interiors are=, def of alt int There for, angle Y and angle Z are complimentary, def of supp angles
I just dont see how angle WZX=100 becuase then you would have a 220 degree triangle, and im pretty sure you cant do that lol
EXACTLYY>
I'm confused,
lol i am stumped sorry:/
Can you tag ppl?
Segment WX is parallel to segment ZY------GIVEN If angle ZYW is 30° and angle ZWY is 20°, then angle WZX is 100°----------CONDITIONAL STATEMENT (What I have so far)
@trumpetmaster7777 help?
@phi,@robtobey,@hba
@rosedewittbukater
@hba
Maybe they can help:)
@jim_thompson5910
first draw it out |dw:1369427947529:dw|
since these two lines here |dw:1369428080775:dw| are parallel, this means that these two angles here |dw:1369428101113:dw| are alternate interior angles that are congruent
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