Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

@jim_thompson5910 I multiply the stuff in the first parenthesis by the stuff in the second parenthesis, right? http://www.sketchtoy.com/34803580

OpenStudy (phi):

9 multiplies, then add "like terms"

OpenStudy (anonymous):

9?!

OpenStudy (phi):

yes. 9! what do you get for the first 3 : x^2 times each of the terms on the right side ?

OpenStudy (anonymous):

Ohh, wait, I see why.

OpenStudy (anonymous):

http://www.sketchtoy.com/34804492 Do I multiply 4x by the red equation next?

OpenStudy (phi):

how did you get the red equation? the way to do it is start with x^2, and multiply x^2 times 2x^2 x +6 and write down the answer for each of those then multiply 4x times each of 2x^2 x +6 then multiply -3 times each of 2x^2 x +6

OpenStudy (phi):

do you know how to do \[ x^2 \cdot 2x^2 \]? remember this is the same as \[ x\cdot x \cdot 2 \cdot x \cdot x \] and you can change the order of the multiplies to \[ 2 \cdot x\cdot x \cdot x \cdot x \] and use the "short-hand" x^4 instead of x*x*x*x \[ 2 x^4 \]

OpenStudy (compassionate):

Give me some background information on what you're doing. It appears we're dealing with multiplication of trinomials.

OpenStudy (anonymous):

The worksheet is actually called Multiplication of Polynomials.

OpenStudy (compassionate):

Poly, whateva. Okay, so in order to multiply a trinomial we want to multiply every time by on another.

OpenStudy (anonymous):

I have this down so far http://www.sketchtoy.com/34804492

OpenStudy (compassionate):

http://www.sketchtoy.com/34806815

OpenStudy (compassionate):

Then you just have to add like terms

OpenStudy (anonymous):

So the red equation I have down already.. would I multiply that by 4x now?

OpenStudy (compassionate):

Huh, the 4x in the original equation? You want to multiple every term...

OpenStudy (anonymous):

No, the red equation in this: http://www.sketchtoy.com/34804492 is the product of multiplying x^2 by the original equation.

OpenStudy (compassionate):

http://www.sketchtoy.com/34808129

OpenStudy (compassionate):

Then you multiply by -3

OpenStudy (anonymous):

Whoa, where did that second part come from?

OpenStudy (compassionate):

I multiplied 4x by everyting in the second equation.

OpenStudy (anonymous):

Oh, okay! So then I multiply both the red and blue by -3?

OpenStudy (compassionate):

No. You multiply everything by -3 on the 2nd parenthesis.

OpenStudy (compassionate):

Are you aware of what we're even doing? :/

OpenStudy (anonymous):

Yes, I'm just really really bad at it > . <

OpenStudy (anonymous):

Right there? http://www.sketchtoy.com/34809182

OpenStudy (compassionate):

If I had (x + y + z) (x + y + z) I'd multiply everything by x x^2 + xy + xz Then I'd do the same for every other term yx + y^2 + yz And now time for z zx zy z^2 Does that make sense?

OpenStudy (anonymous):

yes, i'll just wing it i guess.

OpenStudy (compassionate):

http://www.sketchtoy.com/34809503

OpenStudy (anonymous):

and now add all the like terms?

OpenStudy (compassionate):

This is actually really easy I just think you're making it more difficult than it actually is.. http://www.sketchtoy.com/34809753 I second, I'll draw something up for you

OpenStudy (anonymous):

This is too confusing. I'm just going to ask my teacher. Thanks for the help though.

OpenStudy (compassionate):

No no. I'm already drawing something. yOu will wait!

OpenStudy (whpalmer4):

The first term in that initial multiplication is wrong: x^2 * 2x^2 is not 3x^4!

OpenStudy (compassionate):

See what I did here? http://www.sketchtoy.com/34810550 This is literally one of the easiest things you can do in school :/

OpenStudy (whpalmer4):

Here's the way to think about it: Remember the distributive property of multiplication? \[a(b+c) = ab + ac\] We just apply that several times: \[a(b+c+d) = ab + ac + ad\] \[(a+b+c)(d +e + f) = a(d+e+f) + b(d+e+f) + c(d+e+f) \]\[= ad + ae + af + b(d + e + f) + c(d + e + f)\]\[= ad+ae+af + bd + be + bf + c(d + e + f)\]\[= ad + ae + af + bd + be + bf + cd + ce +cf\]

OpenStudy (whpalmer4):

So your problem: \[(x^2+4x-3)(2x^2+x+6) = x^2(2x^2+x+6) + 4x(2x^2+x+6) -3(2x^2+x+6)\]\[=2x^4+x^3+6x^2 + 8x^3+4x^2+24x -6x^2-3x-18\] Collect like terms and you're done!

OpenStudy (whpalmer4):

Sorry if part of it went off the right side, I hope you get the idea...

OpenStudy (anonymous):

@Compassionate That's what I've been doing, I was only one number off. And you know that very last number is a 6, right?

OpenStudy (compassionate):

I thought it was b. Your handwriting is scary ;-; Yea, do what you did for the first one to every term in the first set of parentheses.

OpenStudy (anonymous):

Sorry, homeschooling does horrible things to handwriting. > . < And okay.

OpenStudy (anonymous):

http://www.sketchtoy.com/34812439 This is the first round, right?

OpenStudy (compassionate):

You messed up on the last part. http://www.sketchtoy.com/34812644

OpenStudy (anonymous):

Round 2 is in purple: http://www.sketchtoy.com/34813148

OpenStudy (compassionate):

correct. Now the same for -3

OpenStudy (anonymous):

http://www.sketchtoy.com/34813715 Round 3 in dark blue

OpenStudy (whpalmer4):

Last term in the red should be \(6x^2\) not \(6^2\)

OpenStudy (anonymous):

Oops, thanks for catching that @whpalmer4

OpenStudy (compassionate):

http://www.sketchtoy.com/34813953

OpenStudy (compassionate):

Now add like terms

OpenStudy (anonymous):

I don't know how I would add the last three terms because they aren't like :/

OpenStudy (compassionate):

For simplicity lets add the first two: http://www.sketchtoy.com/34815249

OpenStudy (anonymous):

is it 12x^2

OpenStudy (compassionate):

http://www.sketchtoy.com/34815434

OpenStudy (whpalmer4):

warning, you lost the last part of the sum in that sketch...

OpenStudy (compassionate):

I fixed it.

OpenStudy (whpalmer4):

You're too quick for me :-)

OpenStudy (compassionate):

She just gave up. Ha ha :P

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!