Simplify Please: x^3+8x^2+20x+13/(x+3)(x-2)
It didn't simplify it completely :/
It's all good
Did you figure it out though, @itsallycatt?
No I didn't...
So your problem follows the "sum of cubes" formula, in that \[(a^3+b^3)= (a+b)(a^2-ab+b^2)\]
@jim_thompson5910 over here
Are you sure that is the equation? I don't see any way in which it can be simplified substantially. Then again I might just be missing something.
ohhhh i figured it out, i think haha
That's what I thought... The answer choices are 1/(x+3)(x+4) 1/(x+3)(x-2) 1/(x+4)(x-2) 1/(x+3)(x+1)
multiply (x+3)(x-2) to get a quadratic equation and then use long division to simplify
I'm assuming all of x^3+8x^2+20x+13 is over (x+3)(x-2) If so, then you can expand out (x+3)(x-2) to get x^2+x-6 then you can use polynomial long division to get the quotient for (x^3+8x^2+20x+13)/(x^2 + x - 6)
xD yay jim! haha
(x+3)(x-2) = x^2 + x - 6 and x^3+8x^2+20x+13/ x^2 + x - 6 = (x+7) (x^2 + x - 6) with a remainder of (19x +55)
something seems missing though because none of the answer choices will match the quotient or the remainder so is there more to the problem?
I have no ideaa, that was the problem I was having...
@Jack1 how did you get your (x+7)(x^2 +x - 6)....
none of these match up... do they have brackets around any of the initial question on the top line? 1/(x+3)(x+4) 1/(x+3)(x-2) 1/(x+4)(x-2) 1/(x+3)(x+1)
@Jhannybean long division
No they don't...
Ohhh. nevermind. Gotcha.
(x^2 + x - 6) times x = x^3 +x^2 -6x goes into x^3+8x^2+20x ..cool nvmd
xD yeah this problem is kicking my booty.
@Jhannybean dont feel bad, its not the answerer, its the question, the fact that there's a remainder means that it doesn't simplify into one of the optional answers, so something in the q's wrong, maybe the people who wrote it put a sign wrong... dunno
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