Question

Algebra help please??

Answer 1

HA finally got the first one! lol hang on

Answer 2

\[\sqrt{16c^4} - \sqrt{c^2} + 3\sqrt{c^2} + \sqrt{4c^2}\]

when you break it all down it'll look like

\[\sqrt{16}\sqrt{c^2}\sqrt{c^2} - \sqrt{c^2} + 3\sqrt{c^2} + \sqrt{4}\sqrt{c^2}\]

so simplifying it more

4(c)(c) - c + 3(c) + 2(c)
4c² -c + 3c + 2c

4x² + 4c

:)

Answer 3

*edit that last part

4c² + 4c
*

:)

Answer 4

And the explanation for the second one:

\[\sqrt{3}(2b \sqrt{49} -b)\]

You know the √49 is 7 so

\[\sqrt{3}(2b(7) - b)\]
\[\sqrt{3}(14b - b)\]

so that becomes

√3(13b) :)