express the perimeter of the triangle as a polynomial side 1:) 2x-3 side 2:)x-12 side 3:)7x+1
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jimthompson5910 (jim_thompson5910):
perimeter = sum of all the sides
so you just add up all the sides...ie the 3 expressions
OpenStudy (anonymous):
so would it be... 9x-14
jimthompson5910 (jim_thompson5910):
well focus on the x terms
jimthompson5910 (jim_thompson5910):
add up 2x, x and 7x to get _____
OpenStudy (anonymous):
9x^3?
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jimthompson5910 (jim_thompson5910):
2x+x is 3x
3x+7x = 10x
jimthompson5910 (jim_thompson5910):
so....
2x+x+7x is 10x
jimthompson5910 (jim_thompson5910):
you do NOT say x+x is x^2
or
x+x+x = x^3
that's not correct
OpenStudy (anonymous):
ok I for got that just x is the same as 1x. so the answer is 10x-14
jimthompson5910 (jim_thompson5910):
yep
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OpenStudy (anonymous):
forgot*
jimthompson5910 (jim_thompson5910):
just remember that saying
x+x
is like saying " i have one thing...then I add another thing....so I now have two things total"
OpenStudy (anonymous):
also what determines a polynomial? ex. which expression is a polynomial
1) \[\frac{ 3 }{\sqrt{x} }\] 2) \[\frac{ 2 }{ x }+3x\] 3)\[\sqrt{x} -6\] 4)\[x-\sqrt{6}\]
jimthompson5910 (jim_thompson5910):
if you're dividing by a variable, then it's NOT a polynomial
if the exponent over the variable isn't a whole number, then it's NOT a polynomial
jimthompson5910 (jim_thompson5910):
if you have square roots over the variable, then it's NOT a polynomial
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OpenStudy (anonymous):
so #2 is a polynomial?
jimthompson5910 (jim_thompson5910):
are you dividing by a variable in #2 ?
jimthompson5910 (jim_thompson5910):
ie...is a variable in the denominator
OpenStudy (anonymous):
so not 1 or 2 but 4?
jimthompson5910 (jim_thompson5910):
yep, there is a square root...but it's not over the variable
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