A post is 9 ft from one wall of a room and 40 ft from the wall at right angle to it. How many ft is it from the intersection of the two walls?
Let one wall be the x-axis and let the other wall be the y-axis. The post is at \((4,9)\), the intersection of the walls is \((0,0)\) ---------------------------------------------------------- Distance from (0,0) to (4,9): \[d = \sqrt{4^2+9^2}= \sqrt{16+36}= \sqrt{52} ft\]
Choices: a. 7 b. 21 c. 41 d. 49
Can you use a calculator?
Yup
Aah, okay. Thank You :D
Wait
The post is at (40,9), the intersection of the walls is (0,0) ------------------------------------------------ Distance from (0,0) to (40,9): \[d = \sqrt{40^2+9^2}= \sqrt{1600+81}= 41 ft\]
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Yeah, that's what i mean.
Okay, that's done
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