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Mathematics 12 Online
OpenStudy (anonymous):

help please

jimthompson5910 (jim_thompson5910):

let x = # of type A y = # of type B type A brings in a profit of $45 each, so selling x of them will gain you 45x dollars type B brings in a profit of $35 each, so selling y of them will gain you 35y dollars In total, you'll get a profit of 45x+35y dollars This must be at least $3850, so 45x+35y >= 3850

jimthompson5910 (jim_thompson5910):

you sell a total of x+y printers, so because "You expect to sell at least 100 laser printers this month", this means x+y >= 100

jimthompson5910 (jim_thompson5910):

if you graph those two inequalities, along with x >= 0 y >= 0 you'll get a feasible region and the vertices of that feasible region will be where the min cost occurs

jimthompson5910 (jim_thompson5910):

it turns out that there are 3 vertices and they are (0, 110), (35, 65), (100, 0) these are the points where the boundary lines intersect

jimthompson5910 (jim_thompson5910):

now what you do is plug each vertex into the cost function C = 86x + 130y and see which vertex produces the smallest value of C

sam (.sam.):

How's that possible?

sam (.sam.):

The large tiles used can't even fit the largest area of mosaic

OpenStudy (anonymous):

@.Sam.

OpenStudy (anonymous):

theses are answer we will obtain 0 small tile 6 large tiles minimum cost $27

sam (.sam.):

If the mosaic area is 60x40 then that could be possible

sam (.sam.):

Because for large tiles is 12x6, so when we have 5 of them then it's 60x30, which is inside the 60x40

OpenStudy (anonymous):

we have to solve iit through linear function

OpenStudy (anonymous):

@.Sam.

sam (.sam.):

Area of mosaic=2400 \[12x+6y \leq 2400\]

OpenStudy (anonymous):

how did we get 2400

OpenStudy (anonymous):

and mostt precisely how did we got 60 and 40

OpenStudy (anonymous):

@ash2326

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