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\[x^{3.9}=11x^{3.2} \\ \\ \large \frac{x^{3.9}}{x^{3.2}}=11\] Then use \[\large x^m \div x^n = x^{m-n}\]
so then take ln to both sides right can u show the working fr tht
\[x^{0.7}=11 \\ \\ x=11^{\frac{1}{0.7}}\]
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