Two forces with magnitudes of 200 and 100 pounds act on an object at angles of 60° and 170° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.

Question

amistre64 · Answer

might want to break it down into right triangles

amistre64 · Answer

or, create component vectors to work with ....

anonymous · Answer

direction of force is in the second quadrant
using the law of parallelogram for vector addition 
i.e
resultant force=

anonymous · Answer

$$\sqrt{f1^{2}+f2^{2}-2f1f2\cos{\theta}}$$

anonymous · Answer

where theta is the angly between the two forces

anonymous · Answer

238 pounds

dumbcow · Answer

i would split it into horizontal and vertical components
$$R_x = 200\cos 60 + 100\cos 170$$
$$R_y = 200\sin 60 + 100 \sin 170$$
magnitude:
$$|R| = \sqrt{R_x^{2} + R_y ^{2}}$$
direction:
$$\theta = \tan^{-1} (\frac{R_y}{R_x})$$