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OpenStudy (anonymous):
OpenStudy (mertsj):
Can you find g(6) ??
OpenStudy (anonymous):
14?
OpenStudy (mertsj):
yes. Now find f(6)
OpenStudy (anonymous):
9?
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OpenStudy (mertsj):
Check your sign.
OpenStudy (anonymous):
-9sry
OpenStudy (mertsj):
f/g (6)=f(6)/g(6)
OpenStudy (anonymous):
so -9/14
OpenStudy (mertsj):
And the values that are NOT in the domain of g/f (x) is anything that causes the denominator to be 0. Since the denominator is f(x), set f(x)=0 and solve. Whatever value you get is NOT in the domain of g/f (x)
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OpenStudy (mertsj):
Actually, it asks for g/f (x) so you want g(6) / f(6)=14/-9
OpenStudy (anonymous):
okay so for f/g(6)=14/-9 and to get g/f i just swtich f with 0 in both equations?
OpenStudy (anonymous):
positive in ]3/2,4] and [-∞,-1] and negative between [-1,3/2[and [4+∞[
OpenStudy (mertsj):
g(6)=14
f(6)=-9
g/f (6)=14/-9
OpenStudy (anonymous):
i meant 0
positive in ]3/2,4] and ]-∞,-1] and negative between [-1,3/2[and [4+∞[
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OpenStudy (anonymous):
right mertsj and for g/f?
OpenStudy (mertsj):
\[\frac{g}{f}(x)=\frac{1+x)(-4+x)}{3-2x}\]
OpenStudy (anonymous):
so there is no answer to it except just to make it a fraction?
OpenStudy (mertsj):
So the denominator cannot be 0
so:
\[3-2x \neq 0\]
OpenStudy (mertsj):
Which means:
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OpenStudy (mertsj):
\[3\neq 2x\]
OpenStudy (mertsj):
Which means:
OpenStudy (mertsj):
\[x \neq \frac{3}{2}\]
OpenStudy (anonymous):
okay which means what? lol thats for G/f?
OpenStudy (mertsj):
What question are you trying to answer?
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OpenStudy (anonymous):
the second one g/f
OpenStudy (anonymous):
we got the first but i dont know how to get the second
OpenStudy (mertsj):
Be more specific. What about g/f?
OpenStudy (anonymous):
look at my post with the attchment
OpenStudy (anonymous):
the second one
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OpenStudy (mertsj):
No. You look at it. You are the one who doesn't know what you are trying to find.
OpenStudy (mertsj):
I am well aware of the question. You are not.
OpenStudy (anonymous):
OHHH!
OpenStudy (anonymous):
I am sorry didnt mean to be rude
OpenStudy (anonymous):
im looking for the one that doesnt equal. which is 3/2 right?
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OpenStudy (mertsj):
You weren't rude. I am just trying to help you see that the reason you don't understand the second part is because you don't know what the question is.
OpenStudy (anonymous):
welll arnt in the domain i mean
OpenStudy (anonymous):
okay so what is NOT in the domain is 3/2?
OpenStudy (mertsj):
The question is: Find all values that are NOT in the domain of g/f (x)
OpenStudy (mertsj):
So now, in order to figure this out, I ask you...Why aren't ALL numbers in the domain? And what does that mean anyway. What is a domain?
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OpenStudy (anonymous):
wait what?
OpenStudy (mertsj):
What is the meaning of domain?
OpenStudy (anonymous):
the domain is all possibble inputs
OpenStudy (anonymous):
which make the function work
OpenStudy (mertsj):
Yes. Very good. All possible values of x
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OpenStudy (mertsj):
So I ask you...why can't every number be a possible input?
OpenStudy (anonymous):
to be honest I dont know :|
OpenStudy (mertsj):
The reason is that you have a denominator and the bottom of a fraction cannot be 0
OpenStudy (anonymous):
right yes
OpenStudy (mertsj):
So if there is an input value that causes the denominator to be 0, you have to kick that number out of the domain
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OpenStudy (mertsj):
Is there such a value(s)?
OpenStudy (anonymous):
oh! okay.
OpenStudy (mertsj):
okay what?
OpenStudy (anonymous):
answering the one before sry lol . and is there what values?
OpenStudy (anonymous):
values that can kick out 0?
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OpenStudy (mertsj):
So if there is an input value that causes the denominator to be 0, you have to kick that number out of the domain
Is there such a value(s)?
OpenStudy (anonymous):
so the numbers that arnt in the domain is 0.
OpenStudy (anonymous):
yes there are
OpenStudy (mertsj):
What is it?
OpenStudy (anonymous):
Sry Im not getting it, and by yes there are i meant that there are values that can cause 0 but i dont know in my equation. I dont know at what im looking at :(. As you can see not good at math
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OpenStudy (mertsj):
What is the denominator of:
\[\frac{f}{g}(x)\]
OpenStudy (anonymous):
g
OpenStudy (mertsj):
According to your problem :
g(x)=(1+x)(-4+x)
and
f(x)=3-2x
OpenStudy (mertsj):
Do you agree with that?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
so the D= 14that what we got
OpenStudy (mertsj):
So using those given facts, what is
OpenStudy (anonymous):
sry -9 i mean
OpenStudy (mertsj):
\[\frac{g(x)}{f(x)}\]
OpenStudy (anonymous):
14/-9
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