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Mathematics 16 Online
OpenStudy (anonymous):

PLEASE HELP!

OpenStudy (anonymous):

OpenStudy (mertsj):

Can you find g(6) ??

OpenStudy (anonymous):

14?

OpenStudy (mertsj):

yes. Now find f(6)

OpenStudy (anonymous):

9?

OpenStudy (mertsj):

Check your sign.

OpenStudy (anonymous):

-9sry

OpenStudy (mertsj):

f/g (6)=f(6)/g(6)

OpenStudy (anonymous):

so -9/14

OpenStudy (mertsj):

And the values that are NOT in the domain of g/f (x) is anything that causes the denominator to be 0. Since the denominator is f(x), set f(x)=0 and solve. Whatever value you get is NOT in the domain of g/f (x)

OpenStudy (mertsj):

Actually, it asks for g/f (x) so you want g(6) / f(6)=14/-9

OpenStudy (anonymous):

okay so for f/g(6)=14/-9 and to get g/f i just swtich f with 0 in both equations?

OpenStudy (anonymous):

positive in ]3/2,4] and [-∞,-1] and negative between [-1,3/2[and [4+∞[

OpenStudy (mertsj):

g(6)=14 f(6)=-9 g/f (6)=14/-9

OpenStudy (anonymous):

i meant 0 positive in ]3/2,4] and ]-∞,-1] and negative between [-1,3/2[and [4+∞[

OpenStudy (anonymous):

right mertsj and for g/f?

OpenStudy (mertsj):

\[\frac{g}{f}(x)=\frac{1+x)(-4+x)}{3-2x}\]

OpenStudy (anonymous):

so there is no answer to it except just to make it a fraction?

OpenStudy (mertsj):

So the denominator cannot be 0 so: \[3-2x \neq 0\]

OpenStudy (mertsj):

Which means:

OpenStudy (mertsj):

\[3\neq 2x\]

OpenStudy (mertsj):

Which means:

OpenStudy (mertsj):

\[x \neq \frac{3}{2}\]

OpenStudy (anonymous):

okay which means what? lol thats for G/f?

OpenStudy (mertsj):

What question are you trying to answer?

OpenStudy (anonymous):

the second one g/f

OpenStudy (anonymous):

we got the first but i dont know how to get the second

OpenStudy (mertsj):

Be more specific. What about g/f?

OpenStudy (anonymous):

look at my post with the attchment

OpenStudy (anonymous):

the second one

OpenStudy (mertsj):

No. You look at it. You are the one who doesn't know what you are trying to find.

OpenStudy (mertsj):

I am well aware of the question. You are not.

OpenStudy (anonymous):

OHHH!

OpenStudy (anonymous):

I am sorry didnt mean to be rude

OpenStudy (anonymous):

im looking for the one that doesnt equal. which is 3/2 right?

OpenStudy (mertsj):

You weren't rude. I am just trying to help you see that the reason you don't understand the second part is because you don't know what the question is.

OpenStudy (anonymous):

welll arnt in the domain i mean

OpenStudy (anonymous):

okay so what is NOT in the domain is 3/2?

OpenStudy (mertsj):

The question is: Find all values that are NOT in the domain of g/f (x)

OpenStudy (mertsj):

So now, in order to figure this out, I ask you...Why aren't ALL numbers in the domain? And what does that mean anyway. What is a domain?

OpenStudy (anonymous):

wait what?

OpenStudy (mertsj):

What is the meaning of domain?

OpenStudy (anonymous):

the domain is all possibble inputs

OpenStudy (anonymous):

which make the function work

OpenStudy (mertsj):

Yes. Very good. All possible values of x

OpenStudy (mertsj):

So I ask you...why can't every number be a possible input?

OpenStudy (anonymous):

to be honest I dont know :|

OpenStudy (mertsj):

The reason is that you have a denominator and the bottom of a fraction cannot be 0

OpenStudy (anonymous):

right yes

OpenStudy (mertsj):

So if there is an input value that causes the denominator to be 0, you have to kick that number out of the domain

OpenStudy (mertsj):

Is there such a value(s)?

OpenStudy (anonymous):

oh! okay.

OpenStudy (mertsj):

okay what?

OpenStudy (anonymous):

answering the one before sry lol . and is there what values?

OpenStudy (anonymous):

values that can kick out 0?

OpenStudy (mertsj):

So if there is an input value that causes the denominator to be 0, you have to kick that number out of the domain Is there such a value(s)?

OpenStudy (anonymous):

so the numbers that arnt in the domain is 0.

OpenStudy (anonymous):

yes there are

OpenStudy (mertsj):

What is it?

OpenStudy (anonymous):

Sry Im not getting it, and by yes there are i meant that there are values that can cause 0 but i dont know in my equation. I dont know at what im looking at :(. As you can see not good at math

OpenStudy (mertsj):

What is the denominator of: \[\frac{f}{g}(x)\]

OpenStudy (anonymous):

g

OpenStudy (mertsj):

According to your problem : g(x)=(1+x)(-4+x) and f(x)=3-2x

OpenStudy (mertsj):

Do you agree with that?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so the D= 14that what we got

OpenStudy (mertsj):

So using those given facts, what is

OpenStudy (anonymous):

sry -9 i mean

OpenStudy (mertsj):

\[\frac{g(x)}{f(x)}\]

OpenStudy (anonymous):

14/-9

OpenStudy (anonymous):

using 6 as x

OpenStudy (mertsj):

What is g(x) ?

OpenStudy (anonymous):

(1+x)(-4+x)

OpenStudy (mertsj):

|dw:1369521506541:dw|

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