Question

A baker has a bag of flour that is 11% whole wheat and a bag of flour that is 63% whole wheat. How many cups of each type does the baker need to make 12 cups of a flour mixture that is 50% whole wheat? (1 point)
3 cups of the 11% flour and 9 cups of the 63% flour
9 cups of the 11% flour and 3 cups of the 63% flour
3 cups of the 11% flour and 3 cups of the 63% flour
9 cups of the 11% flour and 9 cups of the 63% flour

Answer 1

hello any one there

Answer 2

Think of this in terms of how much whole wheat there is in each cup. 1 cup of 11% whole wheat = 0.11 C whole wheat and 0.89 C other. 1 cup of 63% whole wheat = 0.63 C whole wheat and 0.37 C other. Let's say A represents the amount of the 11% ww flour you use, and B represents the 63% ww flour. Then we can write A + B = 12, because we want to make 12 cups of flour. We also know that we need to end up with 12 cups * 50% = 6 cups of whole wheat in those 12 cups, so we can write another equation to show how we get that.

Answer 3

\(0.11 * A + 0.63 * B = 6\)

Now we know two equations in two unknowns, and we can solve them by substitution or elimination. Do you know how to do that?

Answer 4

yeah i think

Answer 5

Alternatively, because we have our answer choices in front of us, you could just try plugging them into the second formula and see if they produce a correct result (both sides are equal). But you should really know how to solve them, because most of the time you won't have that option in real life :-)

Answer 6

Try it, I'll check your answer.

Answer 7

X=6/0.11A+0.63B

Answer 8

Here are our two equations:
\[A + B = 12\]\[0.11A + 0.63B = 6\]

I would solve the first equation for A, and substitute that into the second equation:
\[A = 12-B\]\[0.11(12-B)+0.63B = 6\]At this point, multiply both sides by 100 to get rid of the decimals:
\[11(12-B) + 63B = 600\]expand the left side:
\[132 - 11B + 63B = 600\]Solve for \(B\), then use \(A = 12-B\) to find \(A\).

Answer 9

all i get is A=12-B

Answer 10

\[132- 11B + 63B= 600\]Can you move the 132 to the right hand side?

Answer 11

it will be B=9

Answer 12

Yes!

Answer 13

so th answer will be b or d

Answer 14

9 cups of the 11% flour and 9 cups of the 63% flour

Answer 15

Only one matches our problem setup. Look at what I wrote above about what A and B represented.

Answer 16

Also, we only are making 12 cups of flour, so d) can't be correct, because that would make 18 cups.

Answer 17

Similarly, c) can't be correct, because that only makes 6 cups of flour. I would take another look at choices a and b...

Answer 18

so it will be 9 cups o the 11% flour and 3 cups of the 63% flour

Answer 19

And look at our equation: even if we don't remember which type of flour is going to be 9 cups, we know that the percentages multiplied by 3 cups and 9 cups must add to 6 cups of whole wheat flour (the thing of interest in the mixture).

Answer 20

Come on, read what I wrote up there again. Here is the relevant sentence: "Let's say A represents the amount of the 11% ww flour you use, and B represents the 63% ww flour. "

Answer 21

if we have 9 cups of 11% flour, that means we have 9 * 0.11 = 0.99 cups of ww flour from that part, and 3*0.63 = 1.89 cups of ww flour from the other part. Does that add up to 6 cups of ww flour in the mixture?

Answer 22

If we have 3 cups of 11% flour, that means we have 3*0.11 = 0.33 cups of ww flour from that part, and 9*0.63 = 5.67 cups of ww flour from the other part. Does that add up to 6 cups of ww flour in the mixture?

Answer 23

already got the answer man