according to the fundamental theorem of algebra, how many zeros does the polynomial function below have? x^4+5x^3+10x^2+20x+24
I have no idea what zeroes are???

Question

according to the fundamental theorem of algebra, how many zeros does the polynomial function below have? x^4+5x^3+10x^2+20x+24
I have no idea what zeroes are???

anonymous · Answer

Zeros are the values of x you get when you set the function to 0 and solve it. They are always equal number of zeros to the degree of the polynomial.

zale101 · Answer

f(x)=x^4+5x^3+10x^2+20x+24
first, find all the factors of 24
24: 1, 2, 3, 4, 6, 8, 12, 24

zale101 · Answer

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zale101 · Answer

for this problem: x^4+5x^3+10x^2+20x+24
1 is the coefficient because it's the beginning

zale101 · Answer

The factors of 24 and 1 are
24: 1, 2, 3, 4, 6, 8, 12, 24
1: is 1

+-{1, 2, 3, 4, 6, 8, 12, 24}

anonymous · Answer

is that how you solve the problem? just seeing how many factors 24 has?

anonymous · Answer

IF you are looking to numerically solve this you would need to find the factors of 24, use that to separate the function into smaller functions. In this case it would be $$(x+2)(x+3)(x^2+4)=0$$ You can verify that these are correct by foiling it out again. Now just solve for the x's. But considering this case gives you imaginary values I don't think that is what you need to do in this case.