Question

Limits,

Can you help me out with this please: http://screencast.com/t/lLsaUJErdX

Answer 1

\[f(x)=2x^3+1\]
\[f'(x)=3x^2\]
\[f'(-1)=3\]

Answer 2

dude f'(x) = 6x^2

Answer 3

@satellite73

Answer 4

oh right

Answer 5

so \(f'(-1)=6\) is the slope

Answer 6

I know the slope, the rest is what I dont know

Answer 7

you have the slope and the point
use the point - slope formula

Answer 8

slope is \(6\) and the point is \((-1,-2)\)

Answer 9

oops \((-1,-1)\)

Answer 10

You see, I already have the solution. But I believe it's wrong http://screencast.com/t/2tjXXmjz9

That's why I asked you guys to cross over it

Answer 11

\[y+1=6(x+1)\]

Answer 12

Is this wrong like I believe http://screencast.com/t/2tjXXmjz9 ?

Answer 13

yeah that is wrong for sure

Answer 14

ty god

Answer 15

I knew it

Answer 16

yes a=1 and not -1

Answer 17

\[f(-1)=2\times (-1)^2+1=-2+1=-1\]

Answer 18

ty

Answer 19

and f(a) =2

Answer 20

its just wrong
don't waste time thinking about it

Answer 21

My final result y = 6x + 7

Answer 22

no y=6x+1

Answer 23

Kinda why

Answer 24

@aditya96